X^2-16x-258=0

Solution for X^2-16x-258=0 equation:

X^2-16X-258=0

a = 1; b = -16; c = -258;
Δ = b2-4ac
Δ = -162-4·1·(-258)
Δ = 1288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1288}=\sqrt{4*322}=\sqrt{4}*\sqrt{322}=2\sqrt{322}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{322}}{2*1}=\frac{16-2\sqrt{322}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{322}}{2*1}=\frac{16+2\sqrt{322}}{2}
$